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Adjacent Angles

In the given ...

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In the given figure, ∠D = ∠E and $\frac{A D}{D B}$ = $\frac{A E}{E C}$ . Prove that BAC is an isosceles triangle.

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Q. In ∆ABC, D and E are points on sides AB and AC respectively such that AD ✕ EC = AE ✕ DB. Prove that DE || BC.

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