In the given figure, D is the mid-point of AB and PC=12AP=3 cm. If AD=DB=4 cm and DE||BP , then AE is
3 cm
Given∶ 12AP=3cm
∴AP=6cm
D is mid-point and DE||BP
⇒ E is the mid-point of AP (Converse of mid-point theorem)
∴AE=12AP=12×6=3 cm
Hence, AE=3 cm