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Question

In the given figure, D is the mid-point of AB and PC=12AP=3 cm. If AD=DB=4 cm and DE||BP , then AE is


A

4 cm

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B

8 cm

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C

3 cm

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D

5 cm

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Solution

The correct option is C

3 cm


Given∶ 12AP=3cm
AP=6cm
D is mid-point and DE||BP
E is the mid-point of AP (Converse of mid-point theorem)
AE=12AP=12×6=3 cm
Hence, AE=3 cm


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