In the given figure, D is the mid-point of ABand PC=12AP=3 cm. If AD=DB=4 cm and DE||BP and BP=8cm, then DE is:
A
4 cm
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B
8 cm
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C
3 cm
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D
5 cm
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Solution
The correct option is A 4 cm Given∶ 12AP=3cm ∴AP=6cm D is mid-point and DE||BP ⇒ E is the mid-point of AP (Converse of mid-point theorem) ∴DE=12BP=12×8=4cm Hence, DE=4cm