In the given figure, ΔABC is congruent to ΔPQR.
What is the perimeter of ΔABC?
20 cm
It is given that ΔABC is congruent to ΔPQR.
Therefore, by CPCT, we get:
AB = PQ, BC = QR, and AC = PR
∴ AB = 5 cm and BC = 8 cm
Perimeter of ΔABC = AB + BC + AC
= (5 + 8 + 7) cm
= 20 cm
Thus, the perimeter of ΔABC is 20 cm.