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In the given figure, DE and BF are the bisectors of ∠ADC and ∠CBA respectively. If DE = BF, AD || BC, AD = BC, AE = 4 cm and BE = 6 cm, then FC + DF equals
दिए गए चित्र में, DE तथा BF क्रमशः ∠ADC तथा ∠CBA के समद्विभाजक हैं। यदि DE = BF, AD || BC, AD = BC, AE = 4 cm तथा BE = 6 cm है, तब FC + DF बराबर है
In the given figure, DE and BF are the bisectors of ∠ADC and ∠CBA respectively. If DE = BF, AD || BC, AD = BC, AE = 4 cm and BE = 6 cm, then FC + DF equals
दिए गए चित्र में, DE तथा BF क्रमशः ∠ADC तथा ∠CBA के समद्विभाजक हैं। यदि DE = BF, AD || BC, AD = BC, AE = 4 cm तथा BE = 6 cm है, तब FC + DF बराबर है
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The correct option is D 10 cm
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