In the given figure, Δ ABC and Δ OBC are both isosceles. It can be concluded that:
A
ΔAOB≅ΔAOC
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B
R.H.S. rule is applied
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C
S.S.S. rule is applied
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D
ΔAOB is not congruent toΔAOC
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Solution
The correct options are AΔAOB≅ΔAOC
C S.S.S. rule is applied In Δ AOB and Δ AOC, AB=AC (Sides of isosceles Δ ABC). OB=OC (Sides of isosceles Δ OBC). AO is common ∴Δ AOB ≅Δ AOC (by SSS congruence) Hence, options A and C are correct.