Question

In the given figure, $\Delta AIB\cong \Delta AIC$

• A. True
• B. False

Answer 1

The correct option is A True

$In△AIB\&△AIC:$

$⟹\angle IAB=\angle IAC\left(given\right)$

$\angle IBA=\angle ICA\left(given\right)$

$IA=IA\left(common\right)$

$\therefore △IAB\cong △IACbyA.A.Sproperty$