In the given figure - AOB-80- The value of x is

The correct option is D 40^∘ We have, ∠ AOB=2∠ ACB [ Angle #160;of #160;the #160;centre #160;is #160;twice #160;at #160;th #16 ...

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Byju's Answer

Standard IX

Mathematics

Angle Subtended by an Arc of a Circle on the Circle and at the Center

In the given ...

Question

In the given figure $∠ A O B = 80^{\circ}$ The value of x is

10^{\circ}

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25^{\circ}

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40^{\circ}

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160^{\circ}

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Solution

The correct option is D $40^{\circ}$
We have,
$∠ A O B = 2 ∠ A C B$
[ Angle of the centre is twice at th angle of circumference \right ]
$80^{\circ} = 2 x$
$∴ x = \frac{80}{2} = 40^{\circ} .$

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Similar questions

Q. In the given figure, AOB is a straight line. If ∠AOC = (3x − 10)°, ∠COD = 50° and ∠BOD = (x + 20)°, then ∠AOC = ?
(a) 40°
(b) 60°
(c) 80°
(d) 50°

In the given figure, AOB is a straight line. If $∠ A O C = (3 x - 10)^{\circ}$ , \angle COD = 50^{\circ}\) and $∠ B O D = (x + 20)^{\circ}$ then $∠ A O C = ?$

(a) $40^{\circ}$

(b) $60^{\circ}$

(d) $50^{\circ}$

Q. Mark (✓) against the correct answer
In the given figure, what value of x will make AOB a straight line?

(a) x = 50
(b) x = 100
(c) x = 60
(d) x = 80

In the given figure, O is the centre of the circle and

∠ A O B = 80^{\circ}

, then match the following

$In the given figure, O is the centre of a circle. If ∠ A O B = 40^{\circ} a n d ∠ B D C = 100^{\circ} t h e n f i n d ∠ O B C .$

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In the given figure ∠AOB=80∘ The value of x is

The correct option is D 40∘We have,∠AOB=2∠ACB[ Angle of the centre is twice at th angle of circumference \right ]80∘=2x∴x=802=40∘.

In the given figure $∠ A O B = 80^{\circ}$ The value of x is

The correct option is D $40^{\circ}$
We have,
$∠ A O B = 2 ∠ A C B$
[ Angle of the centre is twice at th angle of circumference \right ]
$80^{\circ} = 2 x$
$∴ x = \frac{80}{2} = 40^{\circ} .$