Question

In the given figure $DE\parallel BC,AD=2cm,DB=3cmandAE1.6cm$ Then $EC$ is equal to

• A. $1.2cm$
• B. $2.5cm$
• C. $2.4cm$
• D. $4.8cm$

Answer 1

The correct option is C $2.4cm$

If a line drawn parallel to any side of a triangle, divides the other two sides proportionally.

In the given figure $DE\parallel BC$

$\therefore \frac{AD}{BD}=\frac{AE}{CE}$

As given $AD=2cm,DB=3cm$ and $AE=1.6cm$

Let $EC$ be $xcm$

$\therefore \frac{2}{3}=\frac{1.6}{x}$

$\Rightarrow 2x=1.6\times 3$

$\Rightarrow x=\frac{1.6\times 3}{2}=2.4cm$