Question

In the given figure, E is the midpoint of side AC and D is the midpoint of side AB, then

S1 : DE = $\frac{1}{2}$BC and DE || BC

S2 : Midpoint theorem : A line segment joining midpoints of 2 sides of a triangle is parallel to the third side and is half of it.

• A. S1 is true and S2 is false.
• B. S1 is false and S2 is true.
• C. S1 and S2 are both true.
• D. S1 and S2 are both false.

Answer 1

The correct option is C

S1 and S2 are both true.

The mid point theorem states that a line segment joining mid points of two sides of a triangle is parallel to the third side and is half of it.
In other words, in $△$ABC,
DE = $\frac{1}{2}$BC and DE || BC.