Question

Question 12

In the given figure, EFGH is a parallelogram, altitudes FK and FI are 8 cm and 4 cm, respectively. If EF = 10 cm, then the area of EFGH is


(a) $20c{m}^2$
(b) $32c{m}^2$
(c) $40c{m}^2$
(d) $80c{m}^2$

Answer 1

In parallelogram EFGH, EF = HG = 10 cm [given]
Area of parallelogram EFGH = Base $\times$ Corresponding height $=10\times 4=40c{m}^2$