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Triangles on the Same Base and between the Same Parallels

In the given ...

Question

In the given figure, EFGH is a parallelogram, altitudes FK and FI are 8 cm and 4 cm, respectively. If EF = 10 cm, then the area of EFGH is

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Solution

In parallelogram EFGH, EF = HG = 10 cm [given]
Area of parallelogram EFGH = Base $\times$ Corresponding height $= 10 \times 4 = 40 c m^{2}$

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Triangles on the Same Base and between the Same Parallels

Standard IX Mathematics

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