In the given figure, EFGH is formed by joining midpoints of consecutive sides of square ABCD. Figures PQRS and KLMN are also formed similarly. KLMN : ABCD is
A
1 : 4
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B
1 : 8
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C
1 : 16
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D
None of the above
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Solution
The correct option is B 1 : 8 If area of KLMN = A, Areas of outer squares are each two times the inner pne's (as every time the side because 1√2 times) hence Area of ABCD =2×2×2×A=8A So the ratio is 1 : 8