In the given figure, find all the angles.

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Solution

In triangle ABC, using the sum of interior angle property of triangles, we get $∠ A + ∠ B + ∠ C = 180^{o}$ . Hence,
$5 x + 3 x + 2 x = 180^{o} \Rightarrow 10 x = 180^{o}$
$\Rightarrow x = 180^{o} / 10 \Rightarrow x = 18^{o}$
Hence,
$∠ A = 5 x = 90^{o}$
$∠ B = 3 x = 54^{o}$
$∠ C = 2 x = 36^{o}$

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Similar questions

Find all the angles in the following figure.

∠ A O C + ∠ B O D = 266^{\circ}

∠ A O C + ∠ B O C + ∠ B O D = 338^{\circ} .

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∠ 1 = 53^{o}

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