In the given figure, find \(\angle ADG\) and ∠IEJ. ABCD is a rectangle. [4 MARKS]
Steps: 2 Marks
Application of Concepts: 1 Mark
Result: 1 Mark
Since ABCD is a rectangle, therefore AB∥CD
∠EDC=∠EIJ=50∘ (Corresponding Angles).
As ABCD is rectangle so ∠ADC=90∘
⇒∠ADG+∠GDC=90∘
So, ∠ADG=90∘−50∘=40∘.
∠EJI=180∘−105∘=75∘ (Linear pairs of angles);
∠IEJ=180∘−(75∘+50∘) (Angle sum property)
⇒∠IEJ=55∘.