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Question

In the given figure, find \(\angle ADG\) and IEJ. ABCD is a rectangle. [4 MARKS]

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Solution

Steps: 2 Marks
Application of Concepts: 1 Mark
Result: 1 Mark

Since ABCD is a rectangle, therefore ABCD

EDC=EIJ=50 (Corresponding Angles).

As ABCD is rectangle so ADC=90

ADG+GDC=90


So, ADG=9050=40.

EJI=180105=75 (Linear pairs of angles);

IEJ=180(75+50) (Angle sum property)

IEJ=55.


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