Question

In the given figure, find
$\angle PMN$

Answer 1

Sum of angle of $\Delta QMR$

$\begin{array}{c}\angle Q+{100}^0+{25}^0={180}^0\\ \angle Q={180}^0-{100}^0-{25}^0={55}^0\\ \angle PMN=\angle Q={55}^0\end{array}$