Question

In the given figure, find
$\angle PNM$

Answer 1

$\begin{array}{c}In\Delta QMR\\ {100}^0+{25}^{0}Q={180}^0\\ \angle Q={180}^0-{125}^0\\ \angle Q=\angle M={55}^0\left(Al\tan gle\right)\\ sumofangleof\Delta PNM\\ {55}^0+{55}^0+\angle pnm={180}^0\\ \angle PNM={180}^0-{55}^0-{55}^0={70}^0\end{array}$