In the given figure, find the area of parallelogram ABCD, if the area of the shaded triangle is 9 cm2
42 square cm
Given, area of shaded triangle =9 cm2
and base of the triangle = 3 cm
∵ Area of triangle =12×Base×Height
⇒9=12×3×h⇒183=h⇒h=6 cm
∴ Area of parallelogram = Height × Base of parallelogram =6×(3+4)=6×7=42 cm2