Question

In the given figure, find the difference in the values of x and y. Given that AB || CD.

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Answer 1

$\angle$AEG + $\angle$AEH = ${180}^{\circ }$ (Linear pair of angles)

${50}^{\circ }$ + x = ${180}^{\circ }$

x = ${180}^{\circ }$ - ${50}^{\circ }$ = ${130}^{\circ }$ ...(i)

y = ${130}^{\circ }$ ...(ii) (Vertically opposite angles)

x =${130}^{\circ }$ and y = ${130}^{\circ }$

From (i) and (ii), we concluded that x = y

So, the difference in the values of x and y is 0.