In the given figure, find the length of side AB.

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Solution

$In right angle triangle ABD A B^{2} = A D^{2} + B D^{2} . . . (i) In A D C A C^{2} = A D^{2} + D C^{2} A D^{2} = A C^{2} - D C^{2} . . . (i i) Substituting the value of AD from (ii) in eq (i) A B^{2} = A C^{2} - D C^{2} + B D^{2} Substituting the values, we get, A B^{2} = 4^{2} - 3^{2} + 5^{2} A B^{2} = 16 - 9 + 25 = 32$
$\Rightarrow A B = \sqrt{32} = 4 \sqrt{2} u n i t s$ .

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Similar questions

In the given figure, the length of side AB is :

{A B}^{2} + {A C}^{2} = 122

B C = 10

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∠ A B C = 90^{\circ}

B D ⊥ A C

A B = 5.7 c m, B D = 3.8 c m

C D = 4.4 c m

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