In the given figure, find the measure of ∠RQT if PQ = QR and ∠QPR=60∘.
A
60∘
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B
140∘
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C
120∘
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D
100∘
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Solution
The correct option is C120∘ Δ PQR is isosceles since PQ = QR. ∴∠QPR=∠QRP=60∘ ∠RQT is the exterior angle of ΔPQR which is equal to the sum of interior opposite angles ∠P and ∠R.
Hence, ∠RQT=60∘+60∘=120∘.