In the given figure, Find the side $A C^{2}$ of the triangle

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Solution

$\begin{matrix} A C^{2} = A B^{2} + B C^{2} \frac{A B}{A C} = cos θ & \frac{B C}{A C} = sin θ A B^{2} + B C^{2} = A C^{2} ({cos}^{2} θ + {sin}^{2} θ) A B^{2} + B C^{2} = A C^{2} \end{matrix}$

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