In the given figure, find the value of ∠ACB.
45°
40°
75°
115°
∠ABD is an exterior angle to ΔABC.
∠ABD = ∠EBC = 115∘ (vertically opposite angles)
∠ABD = ∠BAC + ∠BCA (exterior angle property)
⟹∠BCA = ∠ABD - ∠BAC = 115∘ - 75∘ = 40∘
In the given figure AB || CD. If ∠EGD=140∘ and ∠GHB=4x∘, then find the value of x.
In the given figure, ABCD is a parallelogram. From the given options, select the values of x
In the given figure, if ∠ACB = 30∘, the value of ∠ACD is .........
In the figure below, △ABC ≅ △BED, ∠DEB = 115∘ and ∠CAB = 25∘, find ∠BDE.