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Question

In the given figure find the value of AOC.
328014_6e9f338e684048229503e53d9447b194.png

A
130
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B
140
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C
150
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D
160
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Solution

The correct option is B 140
IntheabovefigureBAO=30andBCO=40......(1)OA,OBandOCarediameterofcircleHenceOA=OB=OCTheanglesoppositetotheequalsidesareequalBAO=ABOSimilarlyBCO=CBOABO=30andCBO=40[From(1)]NowABC=ABO+CBOABC=30+40=70.........(2)AOC=2ABC=2×70=140[From(2)]HenceoptionBisrightanswer

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