Question

In the given figure, fluid has density ${\rho }_o$ and density of cylinder is $\rho$. The cylinder is in equilibrium.Then, $h_1$ is given by

• A. $\frac{\rho }{{\rho }_o-\rho }{h}_2$
• B. $\frac{\rho }{{\rho }_o+\rho }{h}_2$
• C. $\frac{{\rho }_o-\rho }{\rho }{h}_2$
• D. $\frac{{\rho }_o+\rho }{\rho }{h}_2$

Answer 1

The correct option is A $\frac{\rho }{{\rho }_o-\rho }{h}_2$

$\text{weight}=\text{upthrust}$

$\rho gA(h_1+h_2)={\rho }_{o}gA\left(h_1\right)$

$h_1=\frac{\rho }{{\rho }_o-\rho }{h}_2$