Question

In the given figure (i) and. (ii) DE $\parallel$ BC. Find EC in(i) and AD in (ii).

• A. $EC=24cm$ , $AD=2cm$
• B. $EC=2cm$ , $AD=2.4cm$
• C. $EC=2.4cm$ , $AD=2cm$
• D. $EC=2cm$ , $AD=24cm$

Answer 1

The correct option is D $EC=2cm$ , $AD=24cm$

In $\Delta ABC,DE\parallel BC$
$\therefore$ By Basic Proportionality Theorem, we get
$\frac{AD}{DB}=\frac{AE}{EC}$
$\Rightarrow \frac{1.5}{3}=\frac{1}{EC}\Rightarrow EC=\frac{3\times 1}{1.5}=2cm$
In fig....(ii)
In $\Delta ABC,DE\parallel BC$
$\therefore$ By Basic Proportionality Theorem, we get
$\frac{AD}{DB}=\frac{AE}{EC}$