Question

In the given figure, $I||m$ and is cut by transversal. If $\angle 1={65}^{\circ }$, find the measure of $\angle 6$.

• A. ${115}^{\circ }$
• B. ${55}^{\circ }$
• C. ${65}^{\circ }$
• D. ${25}^{\circ }$

Answer 1

The correct option is A ${115}^{\circ }$

We have, ∠1 = 65 ∠1 = ∠3 (vertically opposite angles) Therefore, ∠3 + ∠6 = 180° 65⁰ + ∠6 = 180⁰

∠6 = 180⁰ – 65⁰

∠6 = 115⁰