In the given figure if AB = 5cm and BC = 12 cm then the radius of the circle is
5 cm
Given ∠ ACB=30∘ and BA = 5 cm, BC = 12 cm
Join O and A, O and B
Now ∠AOB=2×∠ ACB
(∵ The angle subtends by arc at centre is twice that it subtends at any point on the remaining part of ccircumference)
∴ ∠ AOB=60∘
NOw ∵ OA=OB
∴ ∠ ABO=∠ BAO
Let ∠ ABO=x
⇒ x+x+60∘=180∘
∴ x=60∘
∴ ΔAOB is equilateral triangle.
∴ OA=5cm
= Radius of circle