In the given figure if AB = AC and AD bisects ∠BAC, then which of the following are true ?
△BAD≅△CAD by SAS postulate
AD⊥BC
D is the mid point of BC
In △BAD and △CAD
(i) AD = AD ......(common)
(ii) ∠DAB=∠CAD.....(given AD bisects ∠ BAC)
(iii) AB = AC ........(given)
(iv)△BAD≅△CAD ....(SAS postulate)
(v) ∠ADB=∠ADC=x∘ (say)......(cpct)
(vi)2x∘=180∘....(∠ ADB and ∠ ADC lie in a straight line)
x=90∘
∴AD⊥BC
(vii) BD = DC .......(cpct)
(viii) D is the midpoint of BC......(from (vii))
Hence (B), (C) and (D)