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Question

In the given figure if AB = AC and AD bisects BAC, then which of the following are true ?


A

BADCAD by ASA postulate

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B

BADCAD by SAS postulate

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C

ADBC

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D

D is the mid point of BC

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Solution

The correct options are
B

BADCAD by SAS postulate


C

ADBC


D

D is the mid point of BC


In BAD and CAD

(i) AD = AD ......(common)

(ii) DAB=CAD.....(given AD bisects BAC)

(iii) AB = AC ........(given)

(iv)BADCAD ....(SAS postulate)

(v) ADB=ADC=x (say)......(cpct)

(vi)2x=180....( ADB and ADC lie in a straight line)

x=90

ADBC

(vii) BD = DC .......(cpct)

(viii) D is the midpoint of BC......(from (vii))

Hence (B), (C) and (D)


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