In the given figure, if AB = AC, prove that BE = CE.
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Solution

$Given, AB = AC$
We know that the tangents from an external point are equal.
$∴ AD = AF, BD = BE and CF = C E \dots \dots .. (i) Now, AB = AC \Rightarrow AD + DB = AF + FC \Rightarrow AF + DB = AF + FC [from (i)] \Rightarrow DB = FC \Rightarrow BE = C E [from (i)] Hence proved .$

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In the given figure, if AB = AC, prove that BE = CE. Figure

Given,AB=AC We know that the tangents from an external point are equal. ∴AD=AF,BD=BE and CF=CE……..(i)Now,AB=AC⇒AD+DB=AF+FC⇒AF+DB=AF+FC [fromi]⇒DB=FC⇒BE=CE [fromi]Hence proved.

In the given figure, if AB = AC, prove that BE = CE.
Figure

$Given, AB = AC$
We know that the tangents from an external point are equal.
$∴ AD = AF, BD = BE and CF = C E \dots \dots .. (i) Now, AB = AC \Rightarrow AD + DB = AF + FC \Rightarrow AF + DB = AF + FC [from (i)] \Rightarrow DB = FC \Rightarrow BE = C E [from (i)] Hence proved .$