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Question

In the given figure, if AB=AC, prove that BE=EC.
OR
ABC is an isosceles triangle in which AB=AC, circumscribed about a circle, as shown in the given Figure. Prove that the base is bisected by the point of contact.
1009480_c93c2e740cde4874b8fde8e6b77c1d77.png

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Solution

Since tangents from an exterior point to a circle are equal
in length.
AD=AF[Tangents from A](i)
BD=BE[Tangents from B](ii)
CE=CF[Tangents from C](iii)

Now,
AB=AC [Given]
ABAD=ACAD [ Subtracting AD from both sides ]
ABAD=ACAF [ using (i) ]
BD=CF
BE=CF [ using (ii) ]
BE=CE [ using (iii) ]

Hence Proved

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