In the given figure, if AB = BC and ∠BAO=∠BCO=90∘, then which of the following is true?
In △ABO and △CBO
(i) ∠BAO=∠BCO=90∘ ........ (given)
(ii) BO = BO .........(common side)
(iii) AB = BC........ (given)
⇒△ABO≅△CBO ........ (RHS Postulate)
⇒ OA = OC.......(cpct)
⇒ ∠ABO=∠CBO ........(cpct)
∴ If ∠ABO=60∘ then, ∠CBO=60∘.