In the given figure- if AB CD - - APQ -50- and - P RD -127- the value of y is- 77- 127- 130-D- 50-

The correct option is A 77^∘We have, ∠ APR=∠ PRD [alternate angles] ⇒ 50^∘+y=127^∘ ⇒ y=77^∘ ...

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In the given ...

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In the given figure, if $A B | | C D, ∠ A P Q = 50^{\circ} a n d ∠ P R D = 127^{\circ}$ , the value of y is

77^{\circ}

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127^{\circ}

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130^{\circ}

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50^{\circ}

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A B | | C D, ∠ A P Q = 50^{\circ} a n d ∠ P R D = 127^{\circ}

A B | | C D, ∠ A P Q = 50^{\circ} a n d ∠ P R D = 127^{\circ}

In the given figure, if $A B | | C D, ∠ A P Q = 50^{\circ} a n d ∠ P R D = 127^{\circ}$ , the value of y is:

In the figure if AB ||CD, ∠APQ = 50^o and ∠PRD = 127^o then y is equal to

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