In the given figure, if AB||CD,∠APQ=50∘ and ∠PRD=127∘, find the value of y.
Given AB and CD are parallel lines. PR is intersecting both parallel lines so it is a transversal.
Then,
∠APR=∠PRD [alternate angles] (1 marks)
⇒50∘+y=127∘
⇒y=77∘ (1 marks)