In the given figure- if AB CD - - AP Q -50- and - P RD -127- the value of y is-A- 70-B- 127-C- 130-D- 50-

The correct option is A We have, ∠ APR=∠ PRD [alternate angles] ⇒ 50^∘+y=127^∘ ⇒ y=77^∘ ...

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Transversal of Parallel Lines

In the given ...

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In the given figure, if $A B | | C D, ∠ A P Q = 50^{\circ} a n d ∠ P R D = 127^{\circ}$ , the value of y is:

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A B | | C D, ∠ A P Q = 50^{\circ} a n d ∠ P R D = 127^{\circ}

In the given figure, if $A B | | C D, ∠ A P Q = 50^{\circ} a n d ∠ P R D = 127^{\circ}$ , the value of y is:

A B | | C D, ∠ A P Q = 50^{\circ} a n d ∠ P R D = 127^{\circ}

In the figure if AB ||CD, ∠APQ = 50^o and ∠PRD = 127^o then y is equal to

In the given figure, if AB || CD, ∠APQ = 50º and ∠PRD = 127º, find x and y.

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