In the given figure, if AB = DC and BC = AD, then by which postulate is △ABC≅△CDA ?
SSS
SAS
ASA
RHS
In △ABC and △ CDA,
(i) AB = CD ......(given)
(ii) BC = DA ......(given)
(iii) AC = AC .....(common)
⇒ △ABC≅△CDA ....(SSS Postulate )
Hence (A)
In the given figure, if ∠ ABC = ∠ ADC and ∠ BAC = ∠ DAC, then by which postulate is △ABC≅△ADC ?
In the given figure, if ∠ ACB = ∠ CAD = 90∘ and AB = DC, then by which postulate is △ ABC ≅ △ ADC ?