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Question

In the given figure if AB || DE, BAC=35o and CDE=53o, find DCE.
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Solution

DCE=EAB (Alternate angles as AB||DE and AE is transversal)
DEC=35
In DCE, we have
DCE+CED+CED=180 (Angle sum property)
DCE+35+53=180DCE=18088=92

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