Question

In the given figure, if $AB,EF,andCD$ are parallel to each other, then $\angle CZX$ is:

• A. ${100}^{\circ }$
• B. ${120}^{\circ }$
• C. ${110}^{\circ }$
• D. ${90}^{\circ }$

Answer 1

The correct option is B ${120}^{\circ }$

Given figure:

From the figure, we can say that $\angle$ AXZ and $\angle BXP$ are vertically opposite angles.

$\therefore \angle AXZ=\angle BXP={60}^{\circ }$

$\angle$ AXZ and $\angle$ CZX are co-interior angles.
$\therefore \angle AXZ+\angle CZX={180}^{\circ }$

$\Rightarrow {60}^{\circ }+\angle CZX={180}^{\circ }$

$\Rightarrow \angle CZX={180}^{\circ }-{60}^{\circ }={120}^{\circ }$