In the given figure if AB || EF, ∠ABC=70∘ and ∠EFD=40∘, then find x.
A
70∘
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B
40∘
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C
110∘
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D
180∘
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Solution
The correct option is C110∘
In the above figure, AB||EF ∠ABC=70∘and∠EFD=40∘ ∠ABC=∠CEF
[Alternate interior angles] ⇒∠CEF=70∘
Also, in ΔDEF x=∠E+∠F [Exterior angle property of a triangle] ⇒x=70∘+40∘=110∘