Question

In the given figure, if $AB,EF\&CD$ are parallel to each other, then $\angle CZX$ is:

• A. ${100}^{\circ }$
• B. ${100}^{\circ }$
• C. ${120}^{\circ }$

Answer 1

The correct option is C ${120}^{\circ }$

Clearly, from the figure, we can say that
$\angle AXZ={60}^{\circ }$ (Vertically opposite angles)
$\Rightarrow \angle AXZ+\angle XZC={180}^{\circ }$
(co-interior angles)
$\Rightarrow {60}^{\circ }+\angle XZC={180}^{\circ }$
$\Rightarrow \angle XZC={180}^{\circ }-{60}^{\circ }={120}^{\circ }$