$\Rightarrow$ In the given figure, if AB = OA then find the value of $∠ A O B$ .

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Solution

Given,
AB = OA
Since, OA and OB are radius of the circle, so OA = OB
⇒ OA = OB = AB (1 mark)
Hence, ∆OAB is an equilateral triangle.
Hence, $∠ A O B = 60^{\circ}$ . (1 mark)

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⇒In the given figure, if AB = OA then find the value of ∠AOB.

Given, AB = OA Since, OA and OB are radius of the circle, so OA = OB ⇒ OA = OB = AB (1 mark) Hence, ∆OAB is an equilateral triangle. Hence, ∠AOB=60∘. (1 mark)

$\Rightarrow$ In the given figure, if AB = OA then find the value of $∠ A O B$ .

Given,
AB = OA
Since, OA and OB are radius of the circle, so OA = OB
⇒ OA = OB = AB (1 mark)
Hence, ∆OAB is an equilateral triangle.
Hence, $∠ A O B = 60^{\circ}$ . (1 mark)