Question

In the given figure, if ∠ABC = 75° and BG is the bisector of ∠ABC, then the measure of ∠ABG is

Answer 1

Given: ∠ABC = 75°
Since BG is the bisector of ∠ABC.
$\therefore \angle ABG=\angle GBC=\frac{1}{2}\angle ABC$
$\Rightarrow \angle ABG=\frac{1}{2}\times {75}^{\circ }$
$\Rightarrow \angle ABG={\left(37\frac{1}{2}\right)}^{\circ }$