In the given figure,If AC = BC, then the value of ∠OCB is .
A
60°
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B
90°
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C
75°
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D
45°
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Solution
The correct option is B 90° Consider ΔOCA and ΔOCB AC = CB (given), OA = OB (Radii of the circle) OC = OC (common side) ΔOCA≅ΔOCB ⇒∠OCA=∠OCB ∠OCA+∠OCB=180∘ ..... (Linear pair) 2∠OCB=180∘ ∴∠OCB=90∘ ⇒ A line drawn through the centre bisects the chord and is perpendicular to it.