In the given figure, if ∠ACB = 40°, ∠DPB = 120°, find ∠CBD.

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Solution

It is given that ∠ACB = 40° and ∠DPB = 120°

Construction: Join the point A and B

(Angle in the same segment)

Now in $△ B D P$ we have

$∠ D P B + ∠ P B D + ∠ B D P = 180 ° \Rightarrow 120 ° + ∠ P B D + 40 ° = 180 ° \Rightarrow ∠ P B D = 20 °$

Hence

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