Question

In the given figure, if ∠ACB = 40°, ∠DPB = 120°, find ∠CBD.

Answer 1

It is given that ∠ACB = 40° and ∠DPB = 120°

Construction: Join the point A and B

(Angle in the same segment)

Now in $△BDP$ we have

$$\begin{gathered} \angle DPB+\angle PBD+\angle BDP=180° \\ \Rightarrow 120°+\angle PBD+40°=180° \\ \Rightarrow \angle PBD=20° \end{gathered}$$

Hence