In the given figure, if AD = BC and AD || BC, then
In △ACB and △CAD, AD=BC [Given] ∠CAD=∠ACB [Alternate angles] CA=AC [common side] △ACB≅△CAD [SAS congruency] ∴AB=DC [CPCT]
In the given figure if ∠BAC=60∘, AB = AC, then
In the given circle, O is the centre and AD, AE are the two tangents. If BC is also a tangent, then .