In the given figure, if $∠$ ABC = $∠$ ADC and $∠$ BAC = $∠$ DAC, then by which postulate is $△ A B C ≅ △ A D C$ ?

SSS

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SAS

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AAS

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RHS

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Solution

The correct option is C
AAS

In $△ A B C$ and $△ A D C$

(i) $∠ A B C = ∠ A D C$ ......(given)

(ii) $∠ B A C = ∠ D A C$ ......(given)

(iii) AC = AC ......(common)

$\Rightarrow △ A B C ≅ △ A D C$ .... (AAS Postulate)

Hence (C)

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