Question

In the given figure, if $\angle$ACB = ${30}^{\circ }$, then what is the value of $\angle$ACD? [2 Marks]

Answer 1

$\text{In the given figure,}\left[1Mark\right]AD=AB\text{(Given)}DC=BC\text{(Given)}AC\text{is common}\therefore \Delta ADC\cong \Delta ABC\text{(SSS congruence)}$
[1 Mark]
$\text{Hence,}\angle ACD=\angle ACB={30}^{\circ }$
[1 Mark]