Question

In the given figure, if $\angle APB={50}^o$, find the $m\left(arcAXB\right)$.

Answer 1

In the given figure, $\angle APB={50}^o$
We know that
$\angle APB=\frac{1}{2}m(arcA\times B)$ ....[By Inscribed Angle theorem]

$m(arcA\times B)=2\times {50}^o$ $={100}^o$