Question

In the given figure, if $\angle B=\angle ACB={65}^o$ and $\angle D={30}^o$, then

• A. $BC>CA>CD$
• B. $AB=CA<CD$
• C. $BC<CA,CA>CD$
• D. $BC>CA,CA<CD$

Answer 1

Answer: (B)

$AB=CA<CD$

We know that the sides opposite to equal angles are equal.

Given, $\angle B=\angle ACB$

$\Rightarrow AB=AC$ .